Question

If A, B, C, are the angels of triangle ABC, prove that tan A+C/2 =cot B/2

Answer 1

Answer:

Step-by-step explanation:

We know that A+B+C =180

A+C = 180-B

(A+C )/2 = (180-B) /2

(A+C) /2 = 90 - B/2

Put tan on both sides

tan(A+C /2) = tan (90 - B/2)

tan (A+C/2) = cot B/2

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