If A, B, C are the angles of a triangle ABC then prove that:
(i) sin(B+C/2)
=COS(A/2)
(ii) cos^2(A/2)
+ cos^2(B+C/2)
= 1
(iii) tan(A+B/2)
=cot(C/2)
I know you cannot solve this one
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Answer:
cos 8695
Step-by-step explanation:
sin =cos do ur questions yourself
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