If A,B,C are the angles of a triangle show that, sinB cos(C+A) +CosB sin(C+A)=0
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Answer:
CosB SIn
Step-by-step explanation:
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Answer:
A+B+C=π
∴sinBcos(C+A)+cosBsin(C+A)
=sin(A+B+C)
=sinπ=0
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