Question

If A,B,C are the angles of a triangle show that, sinB cos(C+A) +CosB sin(C+A)=0
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Answer 1

Answer:

CosB SIn

Step-by-step explanation:

Answer 2

Answer:

A+B+C=π

∴sinBcos(C+A)+cosBsin(C+A)

=sin(A+B+C)

=sinπ=0

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