If A,B, C are the angles of a triangle show that tana-b/2=cotc/2+b
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Step-by-step explanation:
A+B+C=180
A+B=180--C
A/+B/=90--C/2
TAN(A/+B/2)=TAN(90--C/2)
" =COTC/2
sprao534:
what is given to prove?. what you have proved?
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Please see the attachment
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