If A, B, C are the interior angles of a triangle ABC, show that : a) Cos A+B/2 =Sin C/2
please give the answer
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please give the answer
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A+B+C=180
A+B=180-C
A+B/2=90-C/2
Sin(A+B/2)=COS(90-C/2)
Sin(A+B/2)=CosA/2
Hence,Proved
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