Question

if A,B,C are the interior angles of a Triangle ABC,then prove sin (A+B)÷2=cos c÷2​

Answer 1

Answer:

In triangle

A + B + C = 180

B + C = 180 - A

sin((B+C)/2) = cos A/2

LHS = sin((180-A)/2)

= sin(90-A/2). we know sin(90-∅) = cos∅

= cosA/2

LHS = RHS

Step-by-step explanation:

Answer 2

Step-by-step explanation:

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