Question

If A,B,C are the interior angles of triangle ABC , prove that cosec(A+B/2) = secC/2

Answer 1

Hope it is correct......

Answer 2

Answer:

Step-by-step explanation: for 2 marks

A+B+C=180 (angle sum property)

A+B=180-C

LHS=cosec(A+B)/2

=cosec(180-C)/2

=cosec 90-C/2

=sec C/2

HENCE PROVED

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