Question

If A B C are the mid points of DE EF FD OF TRIANGLE DEF then find the ratio of triangle ABC AND Triangle DEF

Answer 1

First of all let me state this theorem

"The area of triangle formed by joining the mid points of the sides of a triangle is one fourth the area of the original triangle "

So according to this

ar(∆ABC) = 1/4 * ar(∆DEF)

=> 1/4 * 14.4

=> 3.8 cm²

Thus the area of ∆ABC is 3.8cm²

Hope it helps!

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