Math, asked by Mofazzal874, 5 months ago

if a,b,c are the roots of the equation:
 {x}^{3}  - 7 {x}^{2}   + 12x - 11 = 0
,Find the last four digit of
 {a}^{21007}  +  {b}^{21007}  +  {c}^{21007}

Answers

Answered by Smdkaif7860
1

Answer:

Let the roots be a,3a,b.

The Sum of the roots is =4a+b=7 .. (i)

(a)(3a)+(a)(b)+(3a)(b)=4

⇒3a

2

+4ab=4 .. (ii)

The Product of roots is 3a

2

b=−12 .. (iii)

Substituting the value of b from (i) in (ii), we get ,

3a

2

+4a(7−4a)=4

⇒13a

2

−28a+4=0

⇒(a−2)(13a−2)=0

⇒a=2 or a=

13

2

For a=2 , b=−1 (By substituting in (i)). This satisfies equation (iii).

For a=

13

2

, b=

13

83

, this does not satisfy equation (iii).

Hence, the roots are (−1,2,6).

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