Question

if a b c are the sides of a triangle and s be its semiperimeter and (s-a)=90 (s-b)=50 (s-c)=10 then find value of a

Answer 1

Answer:

a = 60

Explanation:

Given that three equations-

s - a = 90     -----------------------------(1)

s - b = 50     -----------------------------(2)

s - c = 10     ----------------------------- (3)

here s  is the semi perimeter, formula for semi perimeter;  

2s = a + b + c  -----------------------------(4)

We add equation (1) + equation (2) + equation (3)

(s - a) + (s - b) + (s - c) = 90 + 50 + 10

3s - (a + b + c) = 150

3s - 2s = 150

s = 150

Now add equation (2) + equation (3)  

(s - b) + (s - c) = 50 + 10

2s - (b + c) = 60

a + b + c - b - c = 60

a = 60

Answer 2

Answer:

Step-by-step explanation:

Answer:

a = 60

Explanation:

Given that three equations-

s - a = 90     -----------------------------(1)

s - b = 50     -----------------------------(2)

s - c = 10     ----------------------------- (3)

here s  is the semi perimeter, formula for semi perimeter;  

2s = a + b + c  -----------------------------(4)

We add equation (1) + equation (2) + equation (3)

(s - a) + (s - b) + (s - c) = 90 + 50 + 10

3s - (a + b + c) = 150

3s - 2s = 150

s = 150

Now add equation (2) + equation (3)  

(s - b) + (s - c) = 50 + 10

2s - (b + c) = 60

a + b + c - b - c = 60

a = 60