Math, asked by nparendramodi7024, 10 months ago

If a,b,c are the three factors of x^3-7x-6 the find a+b+c

Answers

Answered by mysticd
1

Answer:

0

Explanation:

Compare x³+0x²-7x-6 with

Ax³+Bx²+Cx+D ,we get

A=1 , B = 0, C = -7 , D = -6

Sum of the zeroes = -b/a

=> a+b+c = -0/1

=>a+b+c=0

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