If a,b,c are the three factors of x^3-7x-6 the find a+b+c
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Answer:
0
Explanation:
Compare x³+0x²-7x-6 with
Ax³+Bx²+Cx+D ,we get
A=1 , B = 0, C = -7 , D = -6
Sum of the zeroes = -b/a
=> a+b+c = -0/1
=>a+b+c=0
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