If a,b,c are the zeroes of the polynomial x^3-2x^2+kx-m=0 and if a+b=0 show that 2k=m
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For a quadratic polynomial ax
2
+bx+c,
the sum of the zeros =
a
−b
and product of the zeros =
a
c
Here, given polynomial is 3x
2
−2kx+2m and zeros are 2 and 3
Thus,
2+3=
3
−(−2k)
=>5=
3
2k
=>2k=15
=>k=
2
15
and 2×3=
3
2m
=>6×3=2m
=>m=9
Thus, k=
2
15
and m=9
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