Question

If a,b,c are the zeros of p(x)=x³-3x²-6x+8,find abc​

Answer 1

Answer:

-8

Step-by-step explanation:

product of zeroes in cubic polynomial is-d/a

Answer 2

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Since a,b,c are the zeros of p(x)=x³-3x²-6x+8

So

$a + b + c \: = - ( \frac{ - 3}{1} ) = 3$

$ab + bc + ca \: = + ( \frac{ - 6}{1} ) = - 6$

$abc \: = - ( \frac{8}{1} ) = - 8$

So the required answer is - 8

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