if a b c are three events associated with random experiment proved that p a union b union c is equals to be a + b + c c minus b intersection b minus b intersection C minus b a b intersection C plus b a union intersection b intersection c
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Hey there!
Let's prove the above using Venn diagram.
The first attachment shows :- P(A) + P(B)+P(C) -
P( A ∩ B) - P( B ∩ C) - P ( A ∩ C) .
In the Venn diagram represents ,
Yellow represents P(A) .
Green represents P( B)
Blue represents P(C )
White represents -P( A ∩ B) - P( B ∩ C) - P ( A ∩ C) .
The second attachment shows, P(A) + P(B)+P(C) - P( A ∩ B) - P( B ∩ C) - P ( A ∩ C) + P ( A ∩ B ∩C)
The third attachments shows, The Venn diagram of P ( A ∪ B ∪ C) .
Here,
P ( A ∩ B ∩C) is represented by Brown.
P ( A ∪ B ∪ C) is represented by Violet.
By observations, We observe that Area of the second Venn diagram = Area of third Venn diagram.
Hence, We can conclude that P ( A ∪ B ∪ C) = P(A) + P(B)+P(C) - P( A ∩ B) - P( B ∩ C) - P ( A ∩ C) + P ( A ∩ B ∩C) .
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Let's prove the above using Venn diagram.
The first attachment shows :- P(A) + P(B)+P(C) -
P( A ∩ B) - P( B ∩ C) - P ( A ∩ C) .
In the Venn diagram represents ,
Yellow represents P(A) .
Green represents P( B)
Blue represents P(C )
White represents -P( A ∩ B) - P( B ∩ C) - P ( A ∩ C) .
The second attachment shows, P(A) + P(B)+P(C) - P( A ∩ B) - P( B ∩ C) - P ( A ∩ C) + P ( A ∩ B ∩C)
The third attachments shows, The Venn diagram of P ( A ∪ B ∪ C) .
Here,
P ( A ∩ B ∩C) is represented by Brown.
P ( A ∪ B ∪ C) is represented by Violet.
By observations, We observe that Area of the second Venn diagram = Area of third Venn diagram.
Hence, We can conclude that P ( A ∪ B ∪ C) = P(A) + P(B)+P(C) - P( A ∩ B) - P( B ∩ C) - P ( A ∩ C) + P ( A ∩ B ∩C) .
There are 3 attachments. See all of them. View the answer in your browser or kindly visit this page :-
https://brainly.in/question/2810671
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AnmolBalwal:
NICE ANSWER ^^
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