if a,b,c are three natural numbers a.b.c=27846.if a/6=b+4=c-4 then finf a+b+c.
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3
Answer:
your answer is 27486/6
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5
Solution:
Given, if a, b, c be three natural numbers,
abc = 27846 ..... (i)
and a/6 = b + 4 = c - 4
Let, a/6 = b + 4 = c - 4 = k (say)
Then, a = 6k, b = k - 4, c = k + 4
From (i), we get
6k (k - 4) (k + 4) = 27846
or, k (k² - 16) = 4641
or, k³ - 16k - 4641 = 0
or, k³ - 17k² + 17k² - 289k + 273k - 4641 = 0
or, k² (k - 17) + 17k (k - 17) + 273 (k - 17) = 0
or, (k - 17) (k² + 17k + 273) = 0
Here k - 17 =0 gives k = 17
and k² + 17k + 273 = 0 gives imaginary solution for k
Therefore, k = 17
Thus, a = 6 * 17 = 102,
b = 17 - 4 = 13 and
c = 17 + 4 = 21
∴ a + b + c = 102 + 13 + 21 = 136
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