If a, b, c are three vector then prove that [a+b, b+c, c+a] =2[a b c]
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I suppose you know the basic formulae of scalar triple product
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19sunil20pbppi7:
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if da/dt = c×a, db/dt = c×b, then show that: d/dt[a×b] = c×(a×b).
wouldn't it be c^2
wait let me check
ok
its (abc)^2
sorry 2abc
can you solve it
Find the distance of points (1,-2,3)from plane x-y+z = 5 measured parallel to straight. Line: x/2 = y/3 =
(z-1)/-6.
(z-1)/-6.
if you have any answers my question then please please help me
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