If a,b,c are two sides of a triangle and s be its semi perimeter and (s-a) =90. (s-b) =50 , (s-c) =10 then find the value of a
pls give full explanation
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Answer:
a=150
Step-by-step explanation:
s-a+s-b+s-c=90+50+10 =150 ,3s-(a+b+c) we know that sum of a+b+c=2s,substitute a+b+c by 2s so now the equation is 3s-2s=150
so s=150so s-a=90
so
substitute s by 150
so 150-a =90
a=60
hope this helps u buddy
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