If a,b,c are vectors such that a+b+c=0 and |a|=7 |b|=5 |c|=3 then the angle between b and c is ?
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|a|=3,|b|=4,|c|=5
a+b+c=0
a+b =-c
|a+b| =|-c|
|a+b|2 =|-c|2
|a|2 +|b|2 +2a.b =|c|2
9 + 25 +2a.b=49
a.b=3*5
9+25+2ab cos theta=49
15=30cos theta
or cos theta=1/2
theata =60
so angle is 60 degrees
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