Math, asked by goyallakshya931, 5 hours ago

If a(b-c)/b(c-a)=b(c-a)/c(b-a)=r such that a, b, c are non-zero distinct real number and r > 0. Find the value of (2r + 1)^2
pls answer fast

Answers

Answered by prabhakarreddy7712
1

Answer:

(2r+1)(2r_1)

(2r)^2-1^2

Step-by-step explanation:

(2r+1)(2r-1)

2r(2r-1)+1(2r-1)

4r^2-2r+2r-1

(2r)^2-1^2

this is the perfect

answer

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