If a(b-c)/b(c-a)=b(c-a)/c(b-a)=r such that a, b, c are non-zero distinct real number and r > 0. Find the value of (2r + 1)^2
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Answer:
(2r+1)(2r_1)
(2r)^2-1^2
Step-by-step explanation:
(2r+1)(2r-1)
2r(2r-1)+1(2r-1)
4r^2-2r+2r-1
(2r)^2-1^2
this is the perfect
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