Question

If a/b+c , b/c+a , c/a+b are in ap then prove tht a square , b square , c square are in AP

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Answer 1

Answer:

If b/c+a- a/b+c=c/a+b-b/c+a (common difference) mustbe equal

(b^2-a^2+c(b-a))/b+c=(c^2-b^2+a(c-b))/a+b

b^2-a^2=c^2-b^2

which are in AP

Step-by-step explanation: