if ( a+b ) ÷ c = ( b+c ) ÷ a = ( c+a ) ÷ b then prove that each ratio equal to 2 or -1
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(a+b)/c=(b+c)/a=(c+a)/b=k
(a+b)/c=k=>a+b=ck......(1)
(b+c)/a=k=>b+c=ak...(2)
(c+a)/b=k=>c+a=bk...(3)
by eqn (1)-(2)
a-c=k(c-a)......(A)=>k=-1
by eqn (2)-(3)
b-a=k(a-b).....(B)=>k=-1
by eqn (1)-(3)
b-c=k(c-b)....(C)=>k=-1
k= -1 is proved
(a+b)/c=(b+c)/a=(c+a)/b=k
(a+b)/c=k=>a+b=ck......(1)
(b+c)/a=k=>b+c=ak...(2)
(c+a)/b=k=>c+a=bk...(3)
by eqn (1)-(2)
a-c=k(c-a)......(A)=>k=-1
by eqn (2)-(3)
b-a=k(a-b).....(B)=>k=-1
by eqn (1)-(3)
b-c=k(c-b)....(C)=>k=-1
k= -1 is proved
jeevani29:
thanks
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