if a,b,c be in arithmetic progression then the valu of (a+2b-c)(2b+c-a)(a+2b+c)
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Answer: 16abc
Step-by-step explanation:
Just used the basic condition for AP
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If a, b, c are in A. P, then 2b=a+c
(a+2b-c)(2b+c-a)(a+2b+c)
=(2a) (2c)(2a+2c)
=8ac(a+c)
8ac(2b)=16abc
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