Question

If a b c can do in 6 days and a works twice faster than b and thrice faster than c then c alone can do

Answer 1

Let no. of days taken by ‘a’ = x

Since ‘a’ works twice faster as ‘b’ and thrice faster as ‘c’,,

no. of days taken by ‘b’ = 2x

no. of days taken by ‘c’ = 3x

Together they complete the work in 6 days.

(1/x) + (1/2x) + (1/3x) = 1/6

(1/x) ( 1+ (1/2)+ (1/3) ) = 1/6

6+3+2=x

So x=11 days

‘c’ takes 3x days

So ‘c’ take 33 days to complete the work alone.