Question

If a+b+c+d+1/a+b+c+d=2,then the value of (a+b+c+d)^6+1/(a+b+c+d)^6.

Answer 1

=a+b+c+d+1/a+b+c+d=2
=a+b+c+d+1 = 2a+2b+2c+2d
=a+b+c+d = 1
=(a+b+c+d)^6+1/(a+b+c+d)^6 = 1^6+1/1^6
=2