If a:b =C:d and e:f=g:h then (ae+bf) :(ae-bf) equals:
A.(e+f) / (e-f)
B.(cg+dh)/(cg-dh)
C.(ch-dh) /(ch+dh)
D.(e-f) / (e+f)
PLEASE ANSWER AS FAST AS POSSIBLE ITS VERY URGENT.
preet2002:
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39
Answer:
Step-by-step explanation:
a:b=c:d
a/b=c/d..........(i)
e:f=g:h
e/f=g/h........(i)
Multiplying both (i) &(ii)
ae/bf=cg/dh (applying componendo and dividemdo)
ae+bf:ae-bf=cg+dh:cg-dh
Hence proved...
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