Math, asked by 20001mariyam, 1 year ago

If a:b =C:d and e:f=g:h then (ae+bf) :(ae-bf) equals:
A.(e+f) / (e-f)
B.(cg+dh)/(cg-dh)
C.(ch-dh) /(ch+dh)
D.(e-f) / (e+f)
PLEASE  ANSWER AS FAST AS POSSIBLE ITS VERY URGENT.


preet2002: only experts need to answer it
20001mariyam: no i feel everyone in brainly.com are experts thats why i said
20001mariyam: Anyone can answer 
preet2002: alright
vinosharubalitanu: experts has to answer it.
20001mariyam: anyone please help
preet2002: which level question
Anonymous: B is correct. I think.

Answers

Answered by rahman749951
39

Answer:


Step-by-step explanation:

a:b=c:d

a/b=c/d..........(i)

e:f=g:h

e/f=g/h........(i)

Multiplying both (i) &(ii)

ae/bf=cg/dh (applying componendo and dividemdo)

ae+bf:ae-bf=cg+dh:cg-dh

Hence proved...


Answered by chestanowal
8

Answer:

Step-by-step explanation:

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