if a,b,c,d are first 4 two digit composite numbers.if a+b+c+d+e is a perfect square then tha value of e
Answers
Answered by
9
first4 two digit composite numbers are 10,12,14,15
so a =10,b=12 c=14 d = 15
their sum
10+12+14+15=51
so the nearest square to this number is 64=8²
51+e=64
e=13
THE ANSWER IS 13
so a =10,b=12 c=14 d = 15
their sum
10+12+14+15=51
so the nearest square to this number is 64=8²
51+e=64
e=13
THE ANSWER IS 13
Answered by
3
Answer:
13
Step-by-step explanation:
first4 two digit composite numbers are 10,12,14,15
so a =10,b=12 c=14 d = 15
their sum
10+12+14+15=51
so the nearest square to this number is 64=8²
51+e=64
e=13
THE ANSWER IS 13
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