if a b c d are first four consecutive odd numbers then 58 positive odd number is
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Answered by
14
Answer:
The answer is 117.
Step-by-step explanation:
Hey mate,
Your solution is here.
•A[k] = 2k + 1
•A[58] = 2(58) + 1
•= > 116 + 1
•= 117. Ans....
Answered by
7
117 is the correct answer
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