if A, B, C, D are four consecutive terms of an ap then find the value of D^2-A^2/C^2-B^2
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Answer:
A=a
B=a+d
C=a+2d
D=a+3d
then
A^2=a^2
B^2=a^2+d^2+2ad
C^2=a^2+4d^2+4ad
D^2=a^2+9d^2+6ad
then
D^2-A^2=9d+6ad......1
C^2-B^2=3d^2+2ad.....2
then1/2
=3(3d^2+2ad)/(3d^2+2ad)
=3/1
=3
is the answer.......
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