Question

if a b c d are in continued proportion prove that (a-b/c+a-c/b)^2-(d-b/c+d-c/b)^2=(a-d)^2x((1/c)^2+(1/b)^2)​

Answer 1

Answer:

S abcd is a continued proportion because one law is there for this so like that

Step-by-step explanation:

and we need to prove the two equation are =