If a,b,c,d are in continued proportion,prove that: a:d=triplicate ratio of (a-b):(b-c)
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As LHS=RHS, hence proved....
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a : d = ( (a-b):(b-c) )³ if a,b,c,d are in continued proportion
Step-by-step explanation:
a,b,c,d are in continued proportion
=> a/b = b/c = c/d = k
=> a = bk
b = ck
c = dk
a = (ck)k = dk * k * k
=> a/d = k³
(a - b)/(b -c) = (bk - b)/(ck - c)
= b(k -1)/c(k - 1)
= b/c
= k
= a/d = ((a - b)/(b -c))³
a : d = ( (a-b):(b-c) )³
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