if a,b,c,d are in g.p. prove that (b+c)(b+d)=(c+a)(c+d).
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(b-c)² + (c-a)² + (d-b)²
=(ar-ar²)² + (ar²-a)² + (ar³-ar)²
=a²(r-r²)² + a²(r²-1)² + a²(r³-r)²
=a²[(r-r²)² + (r²-1)² + (r³-r)²}
=a^2[r^2+r^4-2r^3+r^4+1-2r^2+r^6+r^2-2r^4] \\\\=a^2[r^6+1-2r^3] \\\\=a^2(1-r^3)^2\\\\ =[a(1-r^3)]^2\\\\
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