If a,b,c,d are in G.P. then prove that:
( {a}^{2} - {b}^{2} )( {c}^{2} - {d)}^{2} = {( {b}^{2} - {c}^{2})}^{2}(a
2
−b
2
)(c
2
−d)
2
=(b
2
−c
2
)
2
Answers
Answered by
0
Answer:
a, b, c, d are in G.P
a
2
+b
2
=a
2
(1+r
2
)
b
2
+c
2
=b
2
(1+r
2
)
c
2
+d
2
=c
2
(1+r
2
)
R
1
=
a
2
+b
2
b
2
+c
2
=
a
2
b
2
=r
2
R
2
=
b
2
+c
2
c
2
+d
2
=
b
2
c
2
=r
2
R
1
=R
2
=r
2
=R
So we have
a
2
+b
2
;
b
2
+c
2
=R(a
2
+b
2
)
c
2
+d
2
=R(b
2
+c
2
)
are in G.P.
solution
Answered by
3
Answer:
this answer is too long bcoz
ye questions numerical h
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