If A B C D are interior angle of cyckic quadrilateral prove SinA÷2=cosC÷2
Answers
Answered by
0
since sum of opposite angles of a quadrilateral is 180°
so A+C = 180°
A = 180°-C
A/2 = (180-C) /2
adding sin
sinA/2 = sin(90-C/2) = cosC/2
hence sinA/2 = cosC/2
hence proved
so A+C = 180°
A = 180°-C
A/2 = (180-C) /2
adding sin
sinA/2 = sin(90-C/2) = cosC/2
hence sinA/2 = cosC/2
hence proved
Similar questions