Question

If A,B,C,D be angles of a cyclic quadrilateral,taken in order,prove that: (cos180°-A)+(cos180°+B)+(cos180°+C)-sin(90°+D)=0​

Answer 1

Answer:

Hey mate here is your answer:

Step-by-step explanation:

IN A CYCLIC QUADRILATERAL SUM OF OPPOSITE VERTICES IS SUPPLEMENTARY.

cos180° = 1

The sum of the rest =180° = 1 radian

PI RADIANS =180°

Hence 1-1=0

Hence Proved

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