Math, asked by ankitakumarimzf666, 19 days ago

Х If a + b +c+d+ e = 12, where a, b, c, d &e are positive numbers and a4b3c3de = 4 x 66, then value of (4a + 3b + 3C + d + e) is equal to -​

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Answered by rajinisharma1971
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Step-by-step explanation:

Х If a + b +c+d+ e = 12, where a, b, c, d &e are positive numbers and a4b3c3de = 4 x 66, then value of (4a + 3b + 3C + d + e) is equal to -​

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