If a,b,c,d,e are in A.P.,then the value of a -4b+6c 4d + c ( a) o ( b) 1 ( c) -1 (d) 2
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let d is the common difference and x is the first term of AP
a=x
b=x+d
c=x+2d
d=x+3d
e=x+4d
now ,
a-4b+6c-4d+e=x-4(x+d)+6 (x+2d)-4 (x+3d)+(x+4d)
=x-4x-4d+6x+12d-4x-12d+x+4d
=x-4x+6x-4x+x=0
option a is the correct answer
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