If a, b, c, d, e are in A.P., then the value of a – 4b + 6c – 4d + e is..................
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a,b,c,d,e are in A.P∴b=a+Dc=a+2Dd=a+3De=a+4DHere D is the common difference substitute the values of b,c,d and e in the given expression.a−4b+6c−4d+e=a−4(a+D)+6(a+2D)−4(a+3D)+a+4D=a−4a−4D+6a+12D−4a−12D+a+4D=8a−8a=0
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