Question

If a:b=c:d=e:f=2:1, then (a+2c+3e):(5b+10d+15f) is equal to:

Answer 1

Step-by-step explanation:

in simple way

a=c=e=2 &

b=d=f=1

and just put the values...

i.e.

= [2+2(2)+3(2)] : [(5(1)+10(1)+15(1)]

= (2+4+6) : (5+10+15)

= 12:30

Answer 2

Answer:

2:5

Step-by-step explanation:

a/b= 2/1

a = 2b

Similarly,

c = 2d

e = 2f

(a+2c+3e):(5b+10d+15f)= (2b+ 4d+ 6f): (5b+10d + 15f)

= 2(b +2d +3f) : 5(b + 2d + 3f)

=2 : 5 (by eliminating common

factors)