If a/b=c/d=e/f prove that a²/b²+c²/d²+e²/f² = ac/bd+ce/df+ae/bf
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First, we can observe that ac/bd, ce/df, and ae/bf are multiplication.
Since each number is equal, we can let a/b=c/d=e/f=N.
We now have N²+N²+N²=N×N+N×N+N×N.
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