if a:b=c:d, prove that a+b/b = c+d/d
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Q. If (a + b + c + d) (a b c + d) = (a + b c d) (a b + c d), prove that a: b = c: d.
answer
Rewriting the given, we have
a–b–c+d
a+b+c+d
=
a–b+c–d
a+b–c–d
Now, applying componendo and dividendo
(a–b–c+d)−(a–b–c+d)
(a+b+c+d)+(a–b–c+d)
=
(a–b+c–d)−(a–b+c–d)
(a+b–c–d)+(a–b+c–d)
2(c+d)
2(a+b)
=
2(c−d))
2(a−b)
c+d
a+b
=
c−d
a−b)
a−b
a+b
=
c−d
c+d
Applying componendo and dividendo again, we get
a+b−c+b
a+b+a−b
=
c+d−c+d
c+d+c−d
2b
2a
=
2d
2c
b
a
=
d
c
plzz understand it
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