If A/B=C/D. prove that A+B/C+D= square root (A^2+B^2)/square root(C^2+D^2)
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(a 2+b 2)x 2−2(ac+bd)x+(c 2+d 2)=0 has equal roots.
Therefore, discriminant =0
Thus [2(ac+bd)] 2+4(a 2+b 2)(c 2 +d 2 )
⇒a 2c 2+b 2d 2 +2ac.bd=a 2c 2+a 2d 2 +b 2c 2+b 2d 2
⇒(ad−bc) 2=0$
⇒ad−bc=0
⇒ad=bc
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