if a:b = c:d, than find the value of a^2+b^2/c^2+d^2
Answers
Answered by
3
Answer:
Step-by-step explanation:
let
a/b=c/d =k
so
a=bk c=dk
now
a^2+b^2/c^2+d^2
(bk)^2+b^2/(dk)^2+d^2
b^2k^2+b^2/d^2k^2+d^2
b^2(k^2+1)/d^2(k^2+1)
b^2/d^2
now
a=bk and c=dk
so
a/k=b and c/k=d
b^2/d^2
(a/k)^2/(c/k)^2
a^2/c^2
so
a/c=b/d
by cross multiply
ab=cd
Hope it helps u^_^
aryanm468:
Can I just continue the solution given by Ashi Sharma
yup.
a/b = k, hence ab=kb^2 or ab/k = b^2,similarly cd/k= d^2... Substituting for b^2 and d^2 in b^2/d^2 we reach to ab/cd
yup
Yeah
now check it. i m rght
great.. thanks a lot to both of you..
Wouldn't take the credit lmao, ur welcome
my pleasure.
Answered by
3
a:b = c:d
ie. a/b = c/d
squaring Both sides
a^2/b^2 = c^2/d^2
therefore
a^2 + b^2/b^2 = c^2 + d^2/d^2
therefore (a^2 + b^2)/(c^2 + d^2) =b^2 / d^2
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