If a: b = c: d than prove by K method that a² + c²/b²+ d² =ac/ bd.
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Given : a: b = c : d
To Find : prove by K method that
a²+c² / b²+d² = ac/ bd
Solution:
a: b = c : d
=> a/b = c/d = k
=> a = bk and c = dk
LHS
= (a²+c²)/ (b²+d² )
= ( (bk)² + (dk)² )/ (b² + d²)
= k²(b² + d²)/(b² + d²)
= k²
RHS
= ac/bd
= bk.dk/bd
= bdk²/bd
= k²
LHS = RHS = k²
QED
Hence proved
a²+c² / b²+d² = ac/ bd if a:b= c:d
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