if a, b, c, d...... x, y, z stand for distinct numbers, find the value of x-a (x-b) (x-c)....... (x-y) (x-z)
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Given: a, b, c, d...... x, y, z stand for distinct numbers.
To find: The value of x-a (x-b) (x-c)....... (x-y) (x-z).
Solution:
- Now we have given that a, b, c ...... x, y, z takes different values. So they are all independent from each other.
- So when we compute x-a, we will always get an integer, either positive or negative.
- Similarly, for x-b, we will always get an integer, either positive or negative.
- So moving till x-w again we will always get an integer, which is either positive or negative.
- But now we come at x-x which will result to zero itself.
- So we have the term: (x-a) (x-b) (x-c)....... (x-x) (x-y) (x-z), here, x-x = 0
- So the whole product will be zero irrespective of all other values.
Answer:
The value of x-a (x-b) (x-c)....... (x-y) (x-z) is equal to 0.
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