If A,B,C denote the area of 3 continuous faces of a rectangular solid cuboid and V it's volume , prove that.
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Solution :-
Let,
- Length = l
- breadth = b
- height = h
◆ A = l × h
◆ B = b × h
◆ C = l × b
- Volume = V
- V= l × b × h
† squaring on both side †
V² = l² × b² × h²
V² = ( l × b × h ) × ( l × b × h )
V² = ( l × h ) × ( b × h ) × ( l × b )
V² = A × B × C
HENCE,
PROVED
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simplify [7835 + {752 +(825 + 115-415÷5)} } nhi
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