Question

if a,b,c do not belong to the set {1,2,3----9} then log 10{a+10b+10^2c/10^-4a+10^-3b+10^-2c​

Answer 1

Step-by-step explanation:

15/(x2 - 4) – 2/(x - 2) = 1.

15/(x2 - 22) – 2/(x - 2) = 1.

15/(x + 2)(x - 2) – 2/(x - 2) = 1.

[15 – 2(x + 2)]/[(x + 2)(x - 2)] = 1.

[15 – 2x - 4] /[(x + 2)(x - 2)] = 1.

[11 - 2x]/[(x + 2)(x - 2)] = 1.

11 – 2x = (x + 2)(x - 2).

11 – 2x = x2 - 4.

x2 - 4 = 11 – 2x.

x2 + 2x – 4 – 11 = 0.

x2 + 2x – 15 = 0.

x + 5) (x - 3) = 0.

x + 5 = 0 or, x – 3 = 0

x = -5 or, x = 3.

Therefore, x = -5 and 3.

Answer 2

Answer:

The attachment will help you

Step-by-step explanation:

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