if a + b + c equal to 6, a square + b square + c square equal to 14 cube plus b cube plus c cube equal to 36 then prove that ABC
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a+b+c=6
a square+b square+c square=14
a cube + b cube + c cube=36
Then
a=1
b=2
c=3
1*1+2*2+3*3=16
1*1*1+2*2*2+3*3*3=36
Proved
Hope it helped you
a square+b square+c square=14
a cube + b cube + c cube=36
Then
a=1
b=2
c=3
1*1+2*2+3*3=16
1*1*1+2*2*2+3*3*3=36
Proved
Hope it helped you
tej2089:
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