if a,b,c form a pythagorean triplet such that a=√1225 and a=3b-1 ,then the value of. c is equal to
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Let me help you with this one.
Given that,
a = √ 1225
a = 35
The equation is given as
a = 3 b - 1 ....... (1)
We have to calculate the value of c
i-e. c = ?
First we put the value of "a" in equation (1) to find the value of "b"
a = 3 b - 1
35 = 3 b - 1
35 + 1 = 3 b
36 = 3 b
Simplifying, we get:
b = 12
It is also given that a,b,c form a Pythagorean triplet,
So, from the Pythagorean theorem
c² = a² + b²
c = √ (a² + b²)
Now put the values of "a" and "b" in above equation
c = √ { (35)² + (12)² }
c = √ (1225 + 144)
c = √ 1369
c = 37
which is the required value of "c"
Hope this will help you.
Given that,
a = √ 1225
a = 35
The equation is given as
a = 3 b - 1 ....... (1)
We have to calculate the value of c
i-e. c = ?
First we put the value of "a" in equation (1) to find the value of "b"
a = 3 b - 1
35 = 3 b - 1
35 + 1 = 3 b
36 = 3 b
Simplifying, we get:
b = 12
It is also given that a,b,c form a Pythagorean triplet,
So, from the Pythagorean theorem
c² = a² + b²
c = √ (a² + b²)
Now put the values of "a" and "b" in above equation
c = √ { (35)² + (12)² }
c = √ (1225 + 144)
c = √ 1369
c = 37
which is the required value of "c"
Hope this will help you.
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