If a,b,c form a Pythagorean triplet such that a = 1225 and a=3b-1 then the value of c is what
Answers
Answered by
0
1225 is the square root of 35
hence a=35
a=3b-1
35=3.b-1
35+1=3.b
36=3.b
36/3=b
12=b
hence b=12
and by using Pythagoras therom
c2=a2+b2
c2=35.35+12.12
c2=1225+144
c2=1369
hence c =37
hence a=35
a=3b-1
35=3.b-1
35+1=3.b
36=3.b
36/3=b
12=b
hence b=12
and by using Pythagoras therom
c2=a2+b2
c2=35.35+12.12
c2=1225+144
c2=1369
hence c =37
Similar questions