Question

if a-b-c , i (ac)=17, i (ab) =9 then find|(bc)​

Answer 1

Answer:

Given, in △ABC, ∠B=90

Given, in △ABC, ∠B=90 o

Given, in △ABC, ∠B=90 o

Given, in △ABC, ∠B=90 o ∴AC

Given, in △ABC, ∠B=90 o ∴AC 2

Given, in △ABC, ∠B=90 o ∴AC 2 =AB

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem]

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC 2

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC 2 =17

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC 2 =17 2

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC 2 =17 2 −8

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC 2 =17 2 −8 2

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC 2 =17 2 −8 2

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC 2 =17 2 −8 2 BC

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC 2 =17 2 −8 2 BC 2

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC 2 =17 2 −8 2 BC 2 =289−64=225

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC 2 =17 2 −8 2 BC 2 =289−64=225∴BC=

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC 2 =17 2 −8 2 BC 2 =289−64=225∴BC= 225

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC 2 =17 2 −8 2 BC 2 =289−64=225∴BC= 225

Given, in △ABC, ∠B=90 o ∴AC 2 =AB 2 +BC 2 [∵ Pythagoras theorem] ⇒BC 2 =AC 2 −AB 2 BC 2 =17 2 −8 2 BC 2 =289−64=225∴BC= 225 =15cm